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Subject: Questa vs. NC
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avidan_e
Posts: 16
Online: User is Offline
12/27/2007 2:42 AM  
Hi, In the code below, nc will compile the code only if NC is defined. Otherwise it will issue two compilation errors. Questa on the other hand, will compile the code anyway. Who is right? package x; class z; function new(); `ifndef NC bit x = 1; // Questa compiles this line `else bit x; x = 1; `endif `ifndef NC randomize(); // Questa issues a warning but compiles `else void'(randomize()); `endif endfunction endclass endpackage once again if you want to read this in a normal way open the text file. Cadence guys - can someone please tell me what am I doing wrong that everything shows up as one line? Best, Avidan

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shalom
Posts: 13
Online: User is Offline
12/27/2007 3:20 AM  
Regarding
[code]randomize();[/code]
vs
[code]void'(randomize());[/code]

there is an ambiguity in the IEEE 1800-2005 standard as to whether a function may be called like a task without casting it to void. In the 1800-2008 standard, it is planned to say that it is legal, but will issue a warning.

-- Shalom
TAM
Posts: 56
Online: User is Offline
12/27/2007 6:02 AM  
The Verilog 2001 standard explicitly disallows the setting of an initial value on a variable declared in a function or a task. As the syntax error message says, section 6.2.1 concludes with "Variable declaration assignments are only allowed at the module level."

The SystemVerilog adds a declaration assignment in a package. But I don't see anything in the LRM that goes as far as permitting it in a class function or task. The list of enhancements to tasks and functions given in section 12.1 of the SV LRM doesn't mention anything about variable declaration assignments.

Perhaps someone who knows the SV standard better than myself can give us the final word.
shalom
Posts: 13
Online: User is Offline
12/27/2007 12:22 PM  
6.4 in 1800-2005 says simply,

"A variable can be declared with an initializer, for example:
int i = 0;"

This was intended to be unconditional.

-- Shalom
shalom
Posts: 13
Online: User is Offline
12/27/2007 12:22 PM  
6.4 in 1800-2005 says simply,

"A variable can be declared with an initializer, for example:
int i = 0;"

This was intended to be unconditional.

-- Shalom
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