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Subject: printing struct members:
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zcabeli11
Posts: 27
Online: User is Offline
3/04/2008 12:52 AM  
Hello, i've got a struct with planty of data members, and some methods. i'd like to be able to print all members automatically (without specify each one in particular). i.e. struct X{ A:uint; B:string; C:bool; D:uint; ... }; the function 'print X' will produce: " A = ... B = ... ... " thanks,
nls
Posts: 3
Online: User is Offline
3/04/2008 1:07 AM  
Hi,

you can use the built-in print function:

Specman s> print sys.s
sys.s = s-@0: s of unit: sys
---------------------------------------------- @s
0 a: 1840385568
1 b: FALSE
2 c: 1554590122
3 d: ""

from within your code you can use "print me;".

Nils
vlsi_dude
Posts: 55
Online: User is Offline
3/04/2008 1:57 AM  
Hi....... You can print struct field by taking instance of that struct and printing using "print" statement. e.g. struct X{ A:uint; B:string; C:bool; D:uint; ... }; // Take instance of this struct y : x; print y;
thinkverification
Posts: 28
Online: User is Offline
3/05/2008 2:51 PM  
You can also use the built in print command in conjunction with "message" which makes it more efficient.
This way the verbosity settings will also affect the printing.

For example :

messagef(LOW,"new packet just added \n") { print new_packet };




Yaron
Yaron Ilani
VLSI Verification Specialist
www.ThinkVerification.com
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Forums > Functional Verification > e > printing struct members:


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